If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+36x-136=0
a = 4; b = 36; c = -136;
Δ = b2-4ac
Δ = 362-4·4·(-136)
Δ = 3472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3472}=\sqrt{16*217}=\sqrt{16}*\sqrt{217}=4\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{217}}{2*4}=\frac{-36-4\sqrt{217}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{217}}{2*4}=\frac{-36+4\sqrt{217}}{8} $
| 9e=60 | | 4=n/12 | | 5(x-2)=83 | | 9e-4=86 | | 4x^2-20x+25=55 | | 1.5+w=5 | | 4^x-2^(x+1)-48=0 | | X+2x=3x+12 | | (x÷1/3)+12=(x×2)-3 | | 2^3x+4=128 | | x÷1/3+12=x×2-3 | | (2(4x+10)-70)=10x-40 | | 8x+4-2(1-x)=8+10-6 | | 7a+1=18/2 | | 4b+4b-3=21 | | x-5+9(9)=x-2+8(8) | | 7(2-x)=9x=2(x+7) | | P(x)=150-3x | | 2.5=2.10+k | | 27/b=-9 | | -5/4=-8/3w-3/2 | | 2^2+16x=0 | | (5-3i)(7+2i)=0 | | -7/2-7/3u=7/5 | | -b/12+16=13 | | n/8=5/2 | | 4z-3+11z=-48 | | 3x-5+6x+12/9=1 | | 0(2x-4)=6(x+2) | | 65=6n+7n | | 2=(4+9w) | | 29=11+2y |